TQC+ Python 第2版｜第七章「綜合應用三」詳解答案

SiteName,County,AQI,Pollutant,Status,SO2,CO,03
基隆,基隆市,38,良好,1.7,0.21,34.9,34,26,8,2.7
汐止,新北市,50,良好,0.5,0.27,23.5,25,22,15,9
萬里,新北市,56,懸浮微粒,普通,1.2,0.2,,69,16,2
新店,新北市,42,良好,1.6,0.23,29.5,24,21,9,3.1
土城,新北市,46,良好,1.1,0.21,28.3,25,19,12,3
板橋,新北市,48,良好,1.2,0.31,21.4,17,19,13,10
新莊,新北市,55,細懸浮微粒,普通,1.1,0.34,22,26,
菜寮,新北市,48,良好,1.8,0.22,32,28,25,12,4.4
林口,新北市,53,細懸浮微粒,普通,0,0.2,33.1,33,2
淡水,新北市,43,良好,1.5,0.21,33.8,32,24,13,2

import os
import os.path as op

# 取得目前路徑
curr_path = op.dirname(__file__)

documents = os.listdir(curr_path)

AQIs = []
for d in documents:
    if '2021' in d: #三個資料夾檔名2021開頭
        file_path = op.join(curr_path,d) #串接目前程式路徑及資料夾
        files = os.listdir(file_path) #讀取資料夾下檔案
        for file in files:
            f = op.join(file_path,file) #路徑再串接檔名
            with open(f,'r',encoding='utf-8') as data:
                for row in data.readlines(): 
                    r = row.split(',')
                    if r[1] == '臺中市' and r[2] != '':
                        AQIs.append(eval(r[2]))
print('臺中市的 AQI 平均為',sum(AQIs) / len(AQIs))

stack = [] #左括號append，右括號pop
match = 0 #存放配對好括號對數
unmatch_right = 0 #存放未配對的右括號數


expr = input("請輸入含小括號之四則運算式：")

for x in expr:
    if x == '(':
        stack.append(x)
    elif x == ')':
        if len(stack) != 0:
            stack.pop()
            match += 1
        else:
            unmatch_right += 1

unmatch_left = len(stack)
total_unmatch = unmatch_right + unmatch_left

if total_unmatch == 0:
    print(f"成對小括號數量 = {match}")
else:
    print(f"不成對小括號數量 = {total_unmatch}")